Merge Arrays in one with ES6 Array spread

gistfile1.txt

const arr1 = [1,2,3]
const arr2 = [4,5,6]
const arr3 = [...arr1, ...arr2] //arr3 ==> [1,2,3,4,5,6]

@touhidrahman

You can use this :

let arr1 = [1, 2, 3];
let arr2 = [4, 5, 6];

let concatAndDeDuplicate = (...arrs) => [ ...new Set( [].concat(...arrs) ) ];

concatAndDeDuplicate(arr1, arr2, [7, 8, 9, 2, 4]);
// [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ]

And if you have multiple arrays of potentialy identical objects, you can use this :

Be aware that it's only taking into account the key you passed in your arguments to remove duplicates !

let arr1 = [
  { id: 6, username: 'lorem' },
  { id: 8, username: 'ipsum' }
];
let arr2 = [
  { id: 6, username: 'lorem' },
  { id: 7, username: 'dolor' }
];

let concatAndDeDuplicateObjects = (p, ...arrs) => [].concat(...arrs).reduce((a, b) => !a.filter(c => b[p] === c[p]).length ? [...a, b] : a, []);

concatAndDeDuplicateObjects('id', arr1, arr2);
/*
  [
    { id: 6, username: "lorem },
    { id: 8, username: 'ipsum' },
    { id: 7, username: 'dolor' }
  ]
*/

But if a deep comparison is mandatory to you, you can do this :

let arr1 = [
  { id: 6, username: 'lorem' },
  { id: 8, username: 'ipsum' }
];
let arr2 = [
  { id: 6, username: 'dolor' },
  { id: 7, username: 'sit' }
];

let concatAndDeDuplicateObjectsDeep = (p, ...arrs) => [ ...new Set( [].concat(...arrs).map(a => JSON.stringify(a)) ) ].map(a => JSON.parse(a))

concatAndDeDuplicateObjectsDeep('id', arr1, arr2);

One of the most important difference between the solutions, is that some methods doesn't mutate the original array (i.e. spread operator, or concat function) but the other mutate the original array (i.e. push).

@eveevans exactly, that's one of the best parts from this feature, it also allows you to make array clones.

const arr1 = [1, 2, 3]; // [1, 2, 3]
const arr2 = [...arr1]; //  [1, 2, 3]
arr2[1] = 5; //                 [1, 5, 3]
console.log(arr1); //       [1, 2, 3]

const arr1 = [1, 2, 3]; // [1, 2, 3]
const arr2 = [3, 4, 5]; // [3, 4, 5]

const concatArr = [...arr1, ...arr2]; // [1, 2, 3, 3, 4, 5]
const mergedArr = Array.from(new Set([...concatArr])); // [1, 2, 3, 4, 5]

refer
https://www.interfacecreator.com/2018/09/typescript-array-type-script-type-test.html

const arrayOne = [{ a: "a" }, { b: "b" }, { c: "c" }];
const arrayTwo = [{ d: "d" }, { e: "e" }, { f: "f" }];
const arrayMerge = { ...arrayOne, ...arrayTwo };
console.log(arrayMerge);

this will result { '0': { d: 'd' }, '1': { e: 'e' }, '2': { f: 'f' } }

How can i remove the indices and merge the array because as you see the result is only arrayTwo

@basilbattikhi First of all if you are trying to merge two arrays, the result will be an array(obvious).
Try this,

const arrayOne = [{ a: "a" }, { b: "b" }, { c: "c" }];
const arrayTwo = [{ d: "d" }, { e: "e" }, { f: "f" }];
const arrayMerge = [ ...arrayOne, ...arrayTwo ];
console.log(arrayMerge);

I've noticed a quirk behavior with spread for flattening an array of arrays.
With concat it goes one level deeper //res = [1,2,9,3,4,5,6]

let arrays = [ [1, [2, 9,], 3], [4, [5], [6]] ];

const res = arrays.reduce((acc, curr) => {
   return acc.concat(...curr);
}, []);

This only goes one level of nesting //res = [1, [2,9], 3, 4, [5], [6]]

let arrays = [ [1, [2, 9,], 3], [4, [5], [6]] ];
const res = arrays.reduce((acc, curr) => {
    return [...acc, ...curr];
}, []);

When you want to merge Objects in Array, then

[{a: 1, b: 2}, {a: 3, b: 4}, {a: 5, b: 6, c: 7}].reduce((acc, curr) => ({...acc, ...curr}), {});

will result

{a: 5, b: 6, c: 7}

ddoooppppeeeeee....easiest answer ive ever googled

This is so strange.. I rather use arr3= arr1.concat(arr2)

This way has a lot of performance issues

_travelDevs

Thanks.. Its working. You make my day

I'm getting an error jQuery is not defined?

this es6 solution is also pretty cool
const concat = (...args) => args.flat();
concat([1, 2, 3], [4, 5], [6, 7]); //➞ [1, 2, 3, 4, 5, 6, 7]

I'm getting an error jQuery is not defined?

You need to add jQuery external link in script tag

arr3 = [...arr1, ...arr2]; will fail if any of them are null.

const arr = [[1,2,3], [4,5,6]]
const merged = arr.reduce((a, b) => { a.splice(0, 0, b); return a; }, [])