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Solution to HITCON CTF 16 -- [PPC] Beelzemon
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#!/usr/bin/python | |
''' | |
[email protected] | |
''' | |
from copy import deepcopy | |
from pwn import * | |
a1 = [0, 3] | |
b1 = [1, 2] | |
base = {} | |
# Pre-compute solution for all the n=k cases. Takes about 4 seconds. | |
for i in range(1, 21): | |
A1 = map(lambda x: x - 2**i, a1) | |
B1 = map(lambda x: x - 2**i, b1) | |
base[i] = (A1, B1) | |
a1_temp = deepcopy(a1) | |
for b in b1: | |
a1.append(b + 2**(i + 1)) | |
for a in a1_temp: | |
b1.append(a + 2**(i + 1)) | |
r = remote('52.198.217.117', 6666) | |
while True: | |
try: | |
line = r.readline_regex('\d+ \d+').split(' ') | |
except: | |
print r.recvall() | |
break | |
x = int(line[0]) | |
y = int(line[1]) | |
n = max(x, y) | |
k = min(x, y) | |
print 'n: ' + str(n) + ' k: ' + str(k) | |
# Get the solution for n = k, and generate the solution for n > k. | |
current_base = base[k] | |
a1 = deepcopy(current_base[0]) | |
b1 = deepcopy(current_base[1]) | |
while k < n: | |
k += 1 | |
a1_temp = deepcopy(a1) | |
for b in b1: | |
next = b + 2**k if b < 0 else b - 2**k | |
a1.append(next) | |
for a in a1_temp: | |
next = a + 2**k if a < 0 else a - 2**k | |
b1.append(next) | |
answer = ' '.join([str(i) for i in a1]) | |
r.sendline(answer) |
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