tkizm1/handle.html

## handle.html
<!DOCTYPE html>
<html>
    <head>
        <meta charset="utf-8">
        <meta http-equiv="content-type" content="text/html; charset=UTF-8">
    </head>
    <body>
        <script>
            var result = [
            {"id": 1,"title": "node1","father_node":null},
            {"id": 2,"title": "node1","father_node":1},
                //{"id": 3,"title": "node1","father_node":1},
            {"id": 4,"title": "node1","father_node":null},
            {"id": 5,"title": "node1","father_node":4},
                //{"id": 6,"title": "node1","father_node":4},
            ];
            var target = [];// 目标数据
            for (var i in result) {
                // 遍历数组，每一个单独处理
                console.log(result[i]);
                if(result[i]['father_node']===null)//如果没有上层节点，那么直接把数据放到target
                    target.push(result[i]);
                else{
                    // 如果有上层节点
                    var father = target.filter(
                            function(obj){
                                return obj.id === result[i]['father_node'];
                            }
                    )[0];// 目标节点的id 等于 当前节点的father_node 根据这个条件去查找
                    // https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter
                    if(target[target.indexOf(father)]['nodes']===undefined){
                        // 如果父节点的nodes为空，那么用数组初始化
                        target[target.indexOf(father)]['nodes']=[];
                    }
                    target[target.indexOf(father)]['nodes'].push(result[i]);
                    // 初始化必定已经完成，那么只需要把目标数据放在 上层节点的nodes里
                }
                //console.log(target);
                // 打印结果
                console.log(JSON.stringify(target,null, 4));
            }
        </script>
    </body>
</html>
	<!DOCTYPE html>
	<html>
	<head>
	<meta charset="utf-8">
	<meta http-equiv="content-type" content="text/html; charset=UTF-8">
	</head>
	<body>
	<script>
	var result = [
	{"id": 1,"title": "node1","father_node":null},
	{"id": 2,"title": "node1","father_node":1},
	//{"id": 3,"title": "node1","father_node":1},
	{"id": 4,"title": "node1","father_node":null},
	{"id": 5,"title": "node1","father_node":4},
	//{"id": 6,"title": "node1","father_node":4},
	];
	var target = [];// 目标数据
	for (var i in result) {
	// 遍历数组，每一个单独处理
	console.log(result[i]);
	if(result[i]['father_node']===null)//如果没有上层节点，那么直接把数据放到target
	target.push(result[i]);
	else{
	// 如果有上层节点
	var father = target.filter(
	function(obj){
	return obj.id === result[i]['father_node'];
	}
	)[0];// 目标节点的id 等于当前节点的father_node 根据这个条件去查找
	// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter
	if(target[target.indexOf(father)]['nodes']===undefined){
	// 如果父节点的nodes为空，那么用数组初始化
	target[target.indexOf(father)]['nodes']=[];
	}
	target[target.indexOf(father)]['nodes'].push(result[i]);
	// 初始化必定已经完成，那么只需要把目标数据放在上层节点的nodes里
	}
	//console.log(target);
	// 打印结果
	console.log(JSON.stringify(target,null, 4));
	}
	</script>
	</body>
	</html>