Get local external ip address with nodejs

ip.js

var
    // Local ip address that we're trying to calculate
    address
    // Provides a few basic operating-system related utility functions (built-in)
    ,os = require('os')
    // Network interfaces
    ,ifaces = os.networkInterfaces();


// Iterate over interfaces ...
for (var dev in ifaces) {

    // ... and find the one that matches the criteria
    var iface = ifaces[dev].filter(function(details) {
        return details.family === 'IPv4' && details.internal === false;
    });

    if(iface.length > 0) address = iface[0].address;
}

// Print the result
console.log(address);

Thanks, it worked !! Optimized it further as:

const ip = Object.values(require('os').networkInterfaces()).flat().find(i => i.family == 'IPv4' && !i.internal).address;

Thanks, it worked !! Optimized it further as:

const ip = Object.values(require('os').networkInterfaces()).flat().find(i => i.family == 'IPv4' && !i.internal).address;

I'm sorry Rajat but making code less readable is not an optimization. 😉

Even more condensed with find and flat.

import { networkInterfaces } from 'os';

const ip = Object.values(networkInterfaces()).flat().find(i => i.family == 'IPv4' && !i.internal).address;

Typescript version (added optional chaining):

import { networkInterfaces } from 'os';

const ip = Object.values(networkInterfaces()).flat().find((i) => i?.family === 'IPv4' && !i?.internal)?.address;

thank all of you so much