Created
August 19, 2009 18:07
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Ruby C implementation of Levenshtein
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# C implementation of Levenshtein text distance algorithm, uses RubyInline to call from within Ruby | |
# Wildly faster than the Text gem's Text::Levenshtein | |
# Example: | |
# l = Levenshtein.new | |
# l.distance 'hello', ' hello' | |
# => 1 | |
# Taken from http://www.benallfree.com/2008/10/05/finding-duplicate-text-with-ruby/ | |
require 'inline' | |
class Levenshtein | |
inline do |builder| | |
builder.c " | |
#include <stdlib.h> | |
#include <malloc.h> | |
#include <string.h> | |
static int distance(char *s,char*t) | |
/*Compute levenshtein distance between s and t*/ | |
{ | |
//Step 1 | |
int min, k,i,j,n,m,cost,*d,distance; | |
n=strlen(s); | |
m=strlen(t); | |
if (n==0) return m; | |
if (m==0) return n; | |
d=malloc((sizeof(int))*(m+1)*(n+1)); | |
m++; | |
n++; | |
//Step 2 | |
for(k=0;k<n;k++) | |
{ | |
d[k]=k; | |
} | |
for(k=0;k<m;k++) | |
{ | |
d[k*n]=k; | |
} | |
//Step 3 and 4 | |
for(i=1;i<n;i++) | |
{ | |
for(j=1;j<m;j++) | |
{ | |
//Step 5 | |
if(s[i-1]==t[j-1]) | |
{ | |
cost=0; | |
} else { | |
cost=1; | |
} | |
//Step 6 | |
min = d[(j-1)*n+i]+1; | |
if (d[j*n+i-1]+1 < min) min=d[j*n+i-1]+1; | |
if (d[(j-1)*n+i-1]+cost < min) min=d[(j-1)*n+i-1]+cost; | |
d[j*n+i]=min; | |
} | |
} | |
distance=d[n*m-1]; | |
free(d); | |
return distance; | |
} | |
" | |
end | |
end |
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