A function to verify the ordered nesting of dict members

verify_dict_path.py

def verify_dict_path(dictionary, *args):
    """
    Verify that 'dictionary' contains nested members consistent with the additional arguments to 'verify_dict_path' in order

     e.g. For the_dict = {"a" : {"b" : {"c" : 3}}}
          verify_dict_path(the_dict, "a", "b", "c") == True
          verify_dict_path(the_dict, "a", "b") == True
          verify_dict_path(the_dict, "a", "b", "c", "d") == False
          verify_dict_path(the_dict, "a", "b", "e") == False
    :param dictionary: A dictionary
    :param args: An arbitrary number of arguments indicating a path into 'dictionary' to test for existence
    :return: bool
    """
    # If there are no more args to consider...
    if len(args) < 1:
        return True  # ...return True
    else:
        # If 'dictionary' is still a dict and the next arg is a member of 'dictionary'...
        if isinstance(dictionary, dict) and args[0] in dictionary:
            return verify_dict_path(dictionary[args[0]], *args[1:])  # ...return the result of verify_dict_path on the next level deeper in 'dictionary' with the next arg
        else:  # 'dictionary' is not, in fact, a dictionary OR the next arg is not a member of 'dictionary'
            return False