Handling the results of multiple async ops with JS.

gistfile1.js

var promises = [
	async1(),
	async2(),
	…
	asyncN()
];
/* jQuery: warning, won't swallow exceptions */
	var deferred = $.Deferred();
	$.when.apply($, promises)
		.done(function () { deferred.resolve(promises); })
		.fail(function () { deferred.reject(promises); });
	return deferred.promise();

/* Q: Promises/A+ compliant, plus more */
	/* will resolve with an array of all values
		or reject on first failure */
	var all = Q.all(promises);

	/* or, to wait for all to finish: */
	var handleResults = function (results) {
		results.forEach(function (result) {
			if (result.state === "fulfilled") {
				var value = result.value;
			} else {
				var reason = result.reason;
			}
		});
	};
	Q.allSettled(promises).then(handleResults);

/* Note that with solely a spec-compliant Promise, you'd have to write the code to aggregate with arrays yourself. Luckily, there's libraries to do that for you! */

Yes, Q.all returns a promise, as does Q.allSettled and $.when.

Here's a pretty straightforward way to report all errors so you can roll back if necessary: (obviously it's N loops so you could do it more efficiently, but I'm always willing to sacrifice efficiency for readability)

Q.allSettled(promises).then(function (results) {
    var allSucceeded = results.every(function (result) { return result.state === 'fulfilled'; });
    if (!allSucceeded) {
        var errorResults = results.filter(function (result) { return result.state !== 'fulfilled'; });
        var errors = errorResults.map(function (result) { return result.reason; });
        rollback(errors);
    } else {
        commit();
    }
});

As for "easier" versus "harder", it's that with callback soup (ps i highly recommend reading http://callbackhell.com) the cognitive load to understand what's happening throughout the program is much higher. With promises, even if it's the same amount of code, it's much simpler to look at a line and see "input leads to output" - which should be much simpler to understand.

Yeah, maybe I'm weird, but I see about the same amount of complexity each way.

I'll keep thinking about it.