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Type inference for literal types with Object.fromEntries
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type Primitive = | |
| boolean | |
| number | |
| string | |
| bigint | |
| symbol | |
| null | |
| undefined; | |
type Narrowable = | |
| Primitive | |
| object | |
| {}; | |
type Entry<K extends PropertyKey, V> = [K, V]; | |
/** | |
* @author https://stackoverflow.com/users/2887218/jcalz | |
* @see https://stackoverflow.com/a/50375286/10325032 | |
*/ | |
type UnionToIntersection<Union> = | |
(Union extends any | |
? (argument: Union) => void | |
: never | |
) extends (argument: infer Intersection) => void | |
? Intersection | |
: never; | |
type FromEntries<T extends Entry<K, V>, K extends PropertyKey, V extends Narrowable> = | |
UnionToIntersection< | |
T extends [infer Key, infer Value] | |
? Key extends PropertyKey | |
? Record<Key, Value> | |
: never | |
: never | |
> | |
function fromEntries<T extends Entry<K, V>, K extends PropertyKey, V extends Narrowable>( | |
entries: Iterable<T>, | |
): FromEntries<T, K, V> { | |
return [...entries].reduce( | |
(accumulator, [key, value]) => | |
Object.assign(accumulator, { | |
[key.toString()]: value, | |
}), | |
{} as FromEntries<T, K, V>, | |
); | |
} | |
fromEntries([ | |
['foo', 1], | |
['bar', 2] | |
]); // #ExpectType { foo: 1, bar: 2} |
Good observation. As to the results: I think you'd have to explicitly provide a type argument to xs.map<>
in order to get the results we want. We would have to somehow map over the tuple and feed that type to .map
.
type Entries<T> = {
[K in keyof T]:
T[K] extends Record<any, infer Value>
? Value extends PropertyKey
? [Value, T[K]]
: never
: never
};
type T1 = Entries<typeof xs>; // $ExpectType readonly [ ["foo", { readonly key: 'foo' }], ["bar", { readonly key: 'bar' }] ]
A similar case for UnionToIntersection
for @maktarsis:
interface Path<T extends string> {
path: T;
}
declare function fn<T extends Path<U>, U extends string>(paths: readonly T[]): Result<T>;
type Result<T extends Path<string>> =
UnionToIntersection<
T extends Path<infer Pathname>
? { [index in Pathname]: Pathname }
: never
>;
fn([{ path: 'home' }, { path: 'about' }]); // $ExpectType { home: 'home', about: 'about' }
const paths = [
{ path: 'home' },
{ path: 'about' },
] as const;
fn(paths); // $ExpectType { home: 'home', about: 'about' }
/**
* @author https://stackoverflow.com/users/2887218/jcalz
* @see https://stackoverflow.com/a/50375286/10325032
*/
type UnionToIntersection<Union> =
(Union extends any
? (argument: Union) => void
: never
) extends (argument: infer Intersection) => void
? Intersection
: never;
Use this definition to overload Object.fromEntries
:
type Primitive =
| boolean
| number
| string
| bigint
| symbol
| null
| undefined;
type Narrowable =
| Primitive
| object
| {};
type Entry<K extends PropertyKey, V> = [K, V];
/**
* @author https://stackoverflow.com/users/2887218/jcalz
* @see https://stackoverflow.com/a/50375286/10325032
*/
type UnionToIntersection<Union> =
(Union extends any
? (argument: Union) => void
: never
) extends (argument: infer Intersection) => void
? Intersection
: never;
type FromEntries<T extends Entry<K, V>, K extends PropertyKey, V extends Narrowable> =
UnionToIntersection<
T extends [infer Key, infer Value]
? Key extends PropertyKey
? { [Property in Key]: Value }
: never
: never
>
declare global {
interface ObjectConstructor {
fromEntries<T extends Entry<K, V>, K extends PropertyKey, V extends Narrowable>(entries: Iterable<T>): FromEntries<T, K, V>
}
}
Object.fromEntries([
['foo', 1],
['bar', 2]
]); // #ExpectType { foo: 1, bar: 2}
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Actually, saying
type Entry<K extends PropertyKey, V> = readonly [K, V];
makes sense then, because[K, V]
is assignable toreadonly [K, V]