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# Source code for article:
# https://hakibenita.com/django-markdown

from typing import Optional
import re
import markdown
from markdown.inlinepatterns import LinkInlineProcessor, LINK_RE
from urllib.parse import urlparse

from django.core.exceptions import ValidationError

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from django.db import models


class Theater(models.Model):

    class Meta:
        verbose_name = 'Theater'
        verbose_name_plural = 'Theaters'

    name = models.CharField(max_length=50)

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import pytest

@pytest.fixture
def A():
    return 1

@pytest.fixture
def B():
    return 1

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# https://hakibenita.com/fast-load-data-python-postgresql

from typing import Iterator, Dict, Any, Optional
from urllib.parse import urlencode
import datetime


#------------------------ Profile

import time

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# https://hakibenita.com/how-to-turn-django-admin-into-a-lightweight-dashboard

from django.contrib import admin
from django.db.models import Count, Sum, Min, Max, DateTimeField
from django.db.models.functions import Trunc

from . import models


def get_next_in_date_hierarchy(request, date_hierarchy):

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class TimeLimitedPaginator(Paginator):
    """
    Paginator that enforced a timeout on the count operation.
    When the timeout is reached a "fake" large value is returned instead,

    Why does this hack exist? On every admin list view, Django issues a
    COUNT on the full queryset. There is no simple workaround. On big tables,
    this COUNT is extremely slow and makes things unbearable. This solution
    is what we came up with.
    """

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"""
Custom django checks.

    H001: Field has no verbose name.
    H002: Verbose name should use gettext.
    H003: Words in verbose name must be all upper case or all lower case.
    H004: Help text should use gettext.
    H005: Model must define class Meta.
    H006: Model has no verbose name.
    H007: Model has no verbose name plural.

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# common/admin.py

class InputFilter(admin.SimpleListFilter):
    template = 'admin/input_filter.html'

    def lookups(self, request, model_admin):
        # Dummy, required to show the filter.
        return ((),)

    def choices(self, changelist):