Validação de CPF em Python

cpfvalidate.py

def validate_cpf(cpf):
    ''' Expects a numeric-only CPF string. '''
    if len(cpf) < 11:
        return False    
    
    if cpf in [s * 11 for s in [str(n) for n in range(10)]]:
        return False
    
    calc = lambda t: int(t[1]) * (t[0] + 2)
    d1 = (sum(map(calc, enumerate(reversed(cpf[:-2])))) * 10) % 11
    d2 = (sum(map(calc, enumerate(reversed(cpf[:-1])))) * 10) % 11
    return str(d1) == cpf[-2] and str(d2) == cpf[-1]


'''
The MIT License (MIT)

Copyright (c) 2015 Derek Willian Stavis

Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:

The above copyright notice and this permission notice shall be included in
all copies or substantial portions of the Software.

THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
THE SOFTWARE.
'''

@rafahlobo essa https://github.com/rafahlobo/cpfValidator está aceitando caracteres repetidos: 11111111111 ...

@rafahlobo essa https://github.com/rafahlobo/cpfValidator está aceitando caracteres repetidos: 11111111111 ...

Blz @marcaum54, vou testar aqui e corrijo. Obrigado pelo feedback.

código bem elegante hein parceiro ! []'s