Quick example

filemover.sh

#!/usr/bin/env sh

# Add a sanity check to make sure that the required arguments are there when the script was called
if [[ -z $2 || -z $1 ]]; then         # The "-z" flag tests for a null value
  echo "Sorry, but you need to provide a source and destination directory, like this:"
  echo "  ./filemover.sh source_dir destination_dir"
  exit 1
fi


# Define the variables that we will use to control the script execution
SRC_DIR=$1                            # Reads the source directory as the first script argument
DEST_DIR=$2                           # Reads the destination directory as the second script argument
PREPEND=$(date "+%Y-%m-%d-%H:%m")     # Sets the prepend date as "now" in the format YYYY-MM-DD-hh:mm

# Beginning with SRC_DIR and including any subdirectories, identify all .txt and .zip files
for i in `find $SRC_DIR -type f -name "*.txt" -o -name "*.zip"`;  # Builds an array (including subdirectories) of matching files and iterates over them one at a time
do
  fname=`basename $i`                     # Strips off the path portion of "i" so that we can rename it easily
  nname="$PREPEND-$fname"                 # Assembles the "New name" for the file in the destination
  echo "Copying $fname to $DEST_DIR/$nname"
  cp $i $DEST_DIR/$nname                  # Performs the actual copy
done

# Return the exit code to the shell so we know whether we succeeded or not
exit $?

This is a VERY incomplete example and addresses the question, "how do I copy files with one of two specific extensions from one directory to a different destination, while prepending the copy date to the filename in the destination. It assumes that you'll want to walk subdirectories, but does not maintain the directory structure at the destination.